Predict values using a fitted hfr
model
Usage
# S3 method for hfr
predict(object, newdata = NULL, ...)
Arguments
- object
Fitted 'hfr' model.
- newdata
Matrix or data.frame of new values for
x
at which predictions are to be made.- ...
additional methods passed to
predict
.
Examples
x = matrix(rnorm(100 * 20), 100, 20)
y = rnorm(100)
fit = hfr(x, y, kappa = 0.5)
predict(fit)
#> [1] -0.14595333 0.56218441 0.49389601 -0.39843183 0.02998357 -0.03546952
#> [7] 0.47047794 0.58410030 0.34649740 0.17059760 -0.17752452 0.21183784
#> [13] -0.25223743 -0.41512860 0.40200347 0.44869856 -0.61424595 0.14170820
#> [19] -0.55218602 0.33786122 -0.89794097 -0.47758607 0.98104394 0.19107443
#> [25] 0.83926278 0.02510526 0.07521414 0.81387724 0.08279434 0.21747967
#> [31] -0.03152481 0.26837104 0.05897475 -0.35846671 0.29886948 -0.07490679
#> [37] -0.90139484 -0.88097716 0.03022039 0.30962608 0.19945093 0.48585669
#> [43] -0.33442585 0.04483908 0.11436401 0.71159776 0.17521278 -0.15766845
#> [49] -0.06289798 -0.19535704 0.56296171 -0.35738229 0.08591483 0.41934465
#> [55] 0.34216687 0.17646924 0.19594877 0.21248704 0.46680305 -0.90384340
#> [61] 0.37798139 0.12893804 0.38367729 0.14067588 0.28791829 0.40270882
#> [67] -0.08234859 0.68353646 -0.24533331 0.23646057 -0.40852838 -0.43651197
#> [73] 1.01811205 0.43138404 0.46017953 0.11591545 0.05033100 0.69822312
#> [79] 0.49979801 0.09963576 -0.25810721 -0.03225740 0.63403180 -0.05775505
#> [85] 0.39026220 -0.29707436 -0.35215811 0.19333360 -0.45865237 0.21239880
#> [91] 0.10216911 -0.36412639 0.41879070 0.16950685 -0.09741607 -0.24326368
#> [97] -0.46119709 -0.12780307 0.42695434 0.59945265